Offline
1
timer(time,unmute(pl))
This timer should have the time as "time" from this:
1
local time = tonumber(p[3])
And to send it to a function after the time is over...
(Some kind of a mute script)
Forum
CS2D
Scripts Timer issue.
Timer issue.
14 replies
1 
This timer should have the time as "time" from this:
And to send it to a function after the time is over...
(Some kind of a mute script)
timer(time,"unmute",pl)
Here's the command code and the function:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
elseif cmd == "!mute" then
if rp_Adminlevel[id] >= 2 then
local pl = tonumber(p[2])
local time = tonumber(p[3])
if pl ~= nil then
if time ~= nil then
if time <= 3600 then
if player(pl,"exists") then
if rp_mute[pl] == false then
gmsg("255255000","[Server]: \169255000000"..player(id,"name").." has muted "..player(pl,"name").." for "..time.." seconds.")
rp_mute[pl]=true
timer(time,"unmute",pl)
end
end
else
gmsg2(id,"255255000","[Server]: \169255000000You can't enter more than 1 hour.")
end
else
gmsg2(id,"255255000","[Server]: \169255000000You need to enter time.")
end
end
else
gmsg2(id,"255255000","[Server]: \169255000000You don't have permission.")
end
1
2
3
4
5
6
7
8
9
10
2
3
4
5
6
7
8
9
10
function unmute(pl)
if pl ~= nil then
if player(pl,"exists") then
if rp_mute[pl] == true then
gmsg("255255000","[Server]: \169000255000"..player(pl,"name").." is no longer muted.")
rp_mute[pl]=false
end
end
end
end
Anyway this algorithm is bad because of if player leave a server and there won't any player with ID that was send in timer function, will generate error that this user doesn't exist. Better to use os.time and save its to a variable of specific player.
Send me here a part of the code with say and leave hook only. I will try to change there something.
edited 1×, last 19.10.15 06:13:10 pm
Gaios: that's no problem if the called function checks whether the player's still online. One could use 
freetimer as well. 1
2
2
time=time*10 timer(time,"unmute",pl)
1
2
2
time=time+time+time+time+time+time+time+time+time+time timer(time,"unmute",pl)
1
2
2
time2=time+time+time+time+time+time+time+time+time+time timer(time2,"unmute",pl)
None worked... Stays as milliseconds.
Any help will be grateful.
1
2
2
seconds = 4 milliseconds = seconds * 1000
VADemon: Thanks it worked, guess I haven't used milliseconds in a while so I forgot their meanings, silly me 
I have another problem with a different script.
I don't think I should create a new topic for it though, here's the problem, when I type !vm hello, all VIPs online should see: Player: Hello but they see Player: !vm Hello instead.
I want to remove the command from the script.
Here's the command:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
elseif cmd == "!vm" then local text = tostring(p[2]) if text ~= nil then if rp_Adminlevel[id]== 0 and rp_vip[id]== 1 then for pl = 1,32 do if rp_vip[pl]==1 and rp_Adminlevel[pl]==0 then if string.sub(txt, #txt-1,#txt) == "!vm" then txt = string.sub(txt, 1, #txt-2) msg2(id,"\169128128128VM | "..player(id,"name")..": "..txt) end end else gmsg2(id,"255255000","[Server]: \169255000000You don't have permission.") end end end end
Edit: Still can't solve it :c
edited 1×, last 21.10.15 03:01:44 pm
Mami Tomoe: Do you even know how string.sub works ? 1
2
3
4
5
6
7
8
9
10
11
12
13
2
3
4
5
6
7
8
9
10
11
12
13
local text = "!vm Hello dude" -- If you want to get the first 3 characters you do it like this string.sub(text, 1, 3) -- Returns "!vm" as it starts from the 1st character (!) and ends on the 3rd character (m). -- So if you want to get the further text, string.sub(5, #text) -- Returns "Hello dude" as it starts from the 5th character (H) and ends on the last character (e) (in this case, the string length, that you can get by using #) -- Note that spaces also count as characters -- Another example: myVar = "Hello world" string.sub(myVar, 1, 5) -- Hello string.sub(myVar, 7, 11) -- world
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
elseif cmd == "!vm" then if rp_Adminlevel[id]<= 0 and rp_vip[id]>= 1 then local txt = tostring(p[2]) if txt ~= nil then txt = string.sub(txt, 1, 3) for pl = 1,32 do if rp_vip[pl]==1 and rp_Adminlevel[pl]==0 then if string.sub(txt, #txt-1,#txt) == "!vm" then msg2(id,"\169128128128VM | "..player(id,"name")..": "..txt) end end end end else gmsg2(id,"255255000","[Server]: \169255000000You don't have permission.") end
I tried this and the permission message works but when I do have permission it wont show anything (the msg2 thing should be shown to all VIPs)
pls
Edit: very pls?
edited 1×, last 24.10.15 06:00:01 pm
for _, i in pairs(player(0,'table')) do if rp_vip[i] == 1 then msg2(i,"\169128128128VM | "..player(id,"name")..": "..txt) end end
Gaios: 1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
elseif cmd == "!vm" then for _, i in pairs(player(0,'table')) do if rp_Adminlevel[i]<= 0 and rp_vip[i]>= 1 then local txt = tostring(p[2]) if txt ~= nil then txt = string.sub(txt, 1, 3) for pl = 1,32 do if rp_vip[pl]==1 and rp_Adminlevel[pl]==0 then if string.sub(txt, #txt-1,#txt) == "!vm" then msg2(i,"\169128128128VM | "..player(i,"name")..": "..txt) end end end end else rp_msg2(i,"255255000","[Server]: \169255000000You don't have permission.") end end
I did this but there's the same problem, when I say
!vm hi
As a admin it wont allow it and will show no permission message (good!)
BUT
when I'm vip and say
!vm hi
nothing appears not in the console and not in the server.
. I will help you later. You may use new Command Engine. Gaios: Oh but I'm fine with the one I already have.All I need is when a VIP says !vm <msg> it will send to all VIPs online that message he sent without the !vm in the text.
And only VIPs can use it, not admins.
1